Lynn has one red, one blue, and one yellow shirt to choose from. she also has one blue and one yellow necklace to choose from. lynn chooses a random shirt and necklace for work today. what is the probability of choosing both a blue shirt and a blue necklace?

Lynn has one red, one blue, and one yellow shirt

It means there are 3 shirts in total.

and she has to choose 1 shirt out of 3

So probability of choosing 1 shirt out of 3 = 1/3

She also has one blue and one yellow necklace to choose from

Now she also has to choose 1 necklace out of 2 ,

So probability of choosing 1 necklace out of 2 = 1/2

Now we have to find the

Probability of choosing a shirt and a necklace = 1/3 * 1/2 = 1/6

entering that problem on the tube might get you an answer

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol