Wo urns contain white balls and yellow balls. the first urn contains 3 white balls and 6 yellow balls and the second urn contains 7 white balls and 3 yellow balls. a ball is drawn at random from each urn. what is the probability that both balls are white?

Answer is

Step-by-step explanation:

Given that there are two urns.  First urn contains 3 white balls and 6 yellow balls and the second urn contains 7 white balls and 3 yellow balls.

A ball is drawn from each urn.

Probability for ball from urn I is white = no of white balls/total balls in I urn

Probability for ball from urn II is white = no of white balls/total balls in I urn

Since drawing one ball from each urn is independent of the other we find

Prob that both balls are white=

Prob that ball from I urn is white *Prob that ball from II urn is white

=

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3