Andres graphed the equation x=y^2 on a coordinate plane, while jody graphed the equation y=x^2. the ordered pair (1,1) satisfies both equations. which statement about the ordered pair (1,-1) is correct? a)it shows that jody did not graph a function. b)it shows that aaron did not graph a function. c)it satisfies both equations. d)i satisfies neither equation. can someone explain this to me?

Let's start by determining if the point (1,-1) is on either of the equations graphed. recall, that any point can be represented as (x,y). to determine if the point (1,-1) is on the equation we replace x with 1 and y with -1. then we see if the resulting equation is valid.is (1,-1) on jody' equation? jody' equation is substituting for x and y gives us: therefore the point is on jody's equation.is (1,-1) on andres' equation? andres' equation is substituting for x and y gives us: therefore the point is not on andres' equation.now since it is on jody's equation we know that an x value of 1 is paired with two different y-values (-1 and 1). as there is more than one y-value associated with an x-value of 1, the equation that jody graphed is not a function.