Suppose that circles r and s have a central angle measuring 125°. additionally, circle r has a radius of 2 3 feet and the radius of circle s is 3 4 feet. if the length of the intercepted arc for circle r is 4 9 π feet, what is the length of the intercepted arc for circle s? a) 2π feet b) 5 8 π feet c) 3 2 π feet d) 1 2 π feet

Let
rR> radius of the circle R
rS> radius of the circle S
LR> the length of the intercepted arc for circle R
LS> the length of the intercepted arc for circle S

we have that
rR=2/3 ft
rS=3/4 ft
rR/rS=8/9> rS/rR=9/8
LR=(4/9)π ft

we know thatif Both circle R and circle S have a central angle , the ratio of the radius of circle R to the radius of circle S is equals to the ratio of the length of circle R to the length of circle S

rR/rS=LR/LS> LS=LR*rS/rR> [(4/9)π*9/8]> (1/2)π ft

the answer is
the length of the intercepted arc for circle S is  (1/2)π ft

Yes you do, so £1973.09 - £1473.50 = £499.59 so tim overpaid £499.59 .hope this ; )