Jenya has 12 bills in her wallet. she has a total of $82. if she has twice as many $5 bill as $1 bills, and two more $10 bills than $5 bills, how many of each does she have?

Let Jenya has x , $1 bills.

Now she has twice as many $5 bills.

So $5 bills = 2x

$10 bills are 2 more than $5 bills.

So $10 bills = 2x + 2

The total amount she has $82

So

x($1) + 2x($5) + (2x+2)($10) = $82

x + 10x + 20x + 20 = 82

31x + 20 = 82

Subtracting 20 from both sides

31x = 62

Dividing by 31 on both sides

x = 2

So $1 bills = 2

$5 bills = 2x = 2(2) = 4

$10 bills = 2x + 2 = 2(2) + 2 = 4 + 2 = 6

Also 2 + 4 + 6 = 12 bills

That verifies our answer is correct

So Jenya has 2 dollar 1 bills, 4 dollar 5 bills & 6 dollar 10 bills.

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10 - 8 = -2

  8 - 6 = -2

etc, so -2 is the common difference

step-by-step explanation: