Which equation can be used to represent six added to twice the sum of a number and four is equal to one-half of the difference of three and the number?

Six added to twice the sum of a number and four is equal to one-half of the difference of thee and the number.

Let x be the number.

6 + 2(x + 4) = 1/2 * (3-x)

Find the value of x.

6 + 2x + 8 = 3/2 - x/2
2x + x/2 = 3/2 - 8 - 6
2x + x/2 = 3/2 - 14
2(2x + x/2) = 2(3/2 - 14)
4x + x = 3 - 28
5x = -25
x = -25/5
x = -5

To check: x = -5

6 + 2(x + 4) = 1/2 * (3-x)

6 + 2(-5+4) = 1/2 * (3 - (-5))
6 + 2 (-1) = 1/2 * (3 + 5)
6 - 2 = 1/2 (8)
4 = 4