You are making a poster that will have a uniform border, as shown. the total area of the poster is 722  square inches. find the width of the border to the nearest inch

I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
 PLEASE SEE ATTACHED IMAGE.
 For this case the area is given by:
 A = (22 + x) * (28 + x) = 722
 Rewriting we have:
 616 + 22x + 28x + x ^ 2 = 722
 x ^ 2 + 50x + 616 - 722 = 0
 x ^ 2 + 50x - 106 = 0
 Solving the polynomial we have:
 x1 = 2.04
 x2 = -52.04
 We take the positive root:
 x = 2.04 inches:
 
 The width of the border to the nearest inch is:
 x = 2inches

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12