Hey can you me posted picture of question

 We have the following equation:
 4x2 + 3x-3 = 0
 Using the resolver we have:
 x = (- b +/- root (b2 - 4ac)) / 2a
 Substituting values we have:
 x = (- (3) +/- root ((3) 2 - 4 (4) (- 3))) / 2 (4)
 Rewriting:
 x = (- 3 +/- root (9 + 48)) / 8
 x = (- 3 +/- root (57)) / 8
 The results are:
 x = (- 3 + root (57)) / 8
 x = (- 3 - root (57)) / 8
 
 x = (- 3 + root (57)) / 8
 x = (- 3 - root (57)) / 8
 option D and F