Given: δklm, kl = lm, f ∈ lm m∠kfm = 75º m∠1=m∠2 find: m∠k, m∠l and m∠m

m∠K = m∠M = 70° m∠L = 40°

Step-by-step explanation: ΔKLM is an isosceles triangle, as it has two sides of same length KL = LM, so the angles form with the base are also the same. The sum of all the angles in a triangle is 180°.

The point F in LM forms another triangle: ΔKFM. It is known that m∠KFM is 75° and that the line forming this new triangle cuts the m∠K in half, so:

m∠F + m∠M + .m∠K = 180

75 + x + = 180

x + = 180 - 75

= 105

3x = 210

x = 70

X is the angle in M, m∠M = 70°. Since m∠M = m∠K, m∠K = 70°

Now, to determine m∠L:

m∠M + m∠K + m∠L = 180

70 + 70 + m∠L = 180

m∠L = 180 - 140

m∠L = 40°

In conclusion, m∠M = 70°, m∠K = 70° and m∠L = 40°

2x3 – 6x2 – 14x + 24 square centimeters

if i'm wrong i'm sorry : )