Arhombus with area $840$ has a diagonal of length $40$. what is its side length?

The area of a rhombus is half the product of its diagonals, so the missing diagonal is equal to (2*840)/40 = 42.

we also know that the 2 diagonals bisect the rhombus into 4 identical right triangles.
the legs of the right triangle are equal to half of the diagonals, which in this case are 20 and 21(40/2 & 42/2)

then we can use the Pythagorean theorem to solve for the side length, and get 29    :)

1. 0.3 •4 is the same as 4 groups of 0.32. 7•0.8 is the same as 7 groups of 0.83. it increases by 0.5 every time, so 0.5x4 it increases by 0.9 every time, so 0.9x5. 0.9•12=10.86. 0.47•5=2.35i can finish the next ones in a separate post

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