Factor to find the zeros of 7x +14-105

I'm not sure if you're asking about a linear or quadratic equation here, so I'll write about both.

y = 7x + 14 - 105

First, we need to simplify this:

y = 7x - 91

We can now pull out a greatest common factor:

y = 7(x - 13)

Now, a zero is any number x is set to that makes y equal 0.

In this case, the zero, or x-intercept, would be 13.

y = 7x² + 14x - 105

First, we should set y to 0:

7x² + 14x - 105 = 0

We can pull out a greatest common factor:

7(x² + 2x - 15) = 0

Next, we can factor it into:

7(x + 5)(x - 3) = 0

By the zero-factor property, both (x + 5) and (x - 3) are equal to zero, since their product is zero.  The numbers that would make the equation true are -5 and 3.  The zeros are -5 and 3.

It is the top one. the answer is -7. that is smallest

Answer: b 2 = 1.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

therefore, b 2= 1.