Acircle is centered at the point (5,-4) and it passes through the point (-3,2). the equation of this circle is (x+ )^2+(y+ )^2=

Remember that the general formula for a circle is  (x – h)² + (y – k)² = r², where (h,k) is the coordinate of the center. We already know that (h,k) = (5,-4), since we know the center's coordinates. We need to find r, the radius, using the distance between the center and the point (-3,2). To do this, we can either use the distance formula, or plug in the points in our circle equation and solve for r.Let's do the second one, plugging in and solving for r.We can use the point (-3,2) for (x,y):(x – h)² + (y – k)² = r²(-3 - 5)² + (2 - -4)² = r²(-8)² +(6)² = r²64 + 36 = r²100 = r²r = 10We know that r=10, and that r² = 100Using h, k, and r, we can now solve for the equation of the circle in standard form.The equation of the circle is:(x – 5)² + (y + 4)² = 100

The final equation is (x-5)^2 + (y+4)^2 = 10^2. 

Hopefully this'll help you!

so the perpendicular line goes through the given pointyou would get a perpendicular line at some random location

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.