Acombined total of $49,000 is invested in two bonds that pay 2% and 6.5%simple interest. the annual interest is $2,5100. how much is invested in each bond?

Let x is the bond pay 2% and y is the pay 6.5%
x + y = 49,000 so x = 49,000 - y
0.02x + 0.065y = 2,510
substitute x = 49,000 - y into 0.02x + 0.065y = 2,510

0.02x + 0.065y = 2,510
0.02(49,000 - y) + 0.065y = 2,510
980 - 0.02y + 0.065y = 2,510
0.045y = 1,530
         y = 34,000
         x = 49,000 - y = 49,000 - 34,000 = 15,000

answer
invested $34,000 in the bond that pays 6.5% rate and $15,000 in bond that pays 2% rate

Distance=slopeslope is -2/4which equals-1/2the distance between these two points is -1/2