Recently, the texas junior college teachers association annual conference was held in austin. at the time a taxi ride in austin was $ 1.75 $1.75 for the first 1 5 15 of a mile and $ 0.25 $0.25 for each additional 1 5 15 of a mile. if the distance from one of the convention hotels to the airport is 5.8 5.8 miles, how much will it cost to take a taxi from that hotel to the airport?

The correct question is
Recently, the texas junior college teachers association annual conference was held in austin. at the time a taxi ride in austin was $ 1.75 for the first 1/5 of a mile and $ 0.25 for each additional 1/5 of a mile. if the distance from one of the convention hotels to the airport is 5.8 miles, how much will it cost to take a taxi from that hotel to the airport?

we know that
(1/5) miles is equal to 0.20 miles
so

for the first 0.20 miles> $1.75
Remaining Distance = 5.8 - 0.2 miles = 5.6 miles
5.6/(0.2) =28 (this is the number of (1/5)th of a mile after the 1st (1/5)th
Each of these costs 0.25 dollars
28*0.25 = 7 dollars

total cost=$1.75+$7> $8.75

the answer is
$8.75

Okay so n is going to represent our first number. since the second number of five times greater than n, the second number will be represented as 5n. for us to figure out the two  numbers we need to have  the value of n first. this is going to be done by adding the two numbers together, n and 5n. it can be simplified as 6n, which the problem states is equal to 72. divide 72 by 6n and you can solve for n.  n+5n=726n=72n=(72/6)n=12  now that we know the value of n, we have to multiply 5 times 12 which equals 60. so our two numbers/integers are 12 and 60