Write each of the equations below in standard form (i. e. y = ax^2+bx+c y=ax 2 +bx+c): a. y = 3(x-7)(x+4) y=3(x−7)(x+4) b. y = 2(x-3)^2 + 5 y=2(x−3) 2 +5 c. y = -2(x+3)(x+5) y=−2(x+3)(x+5) d. y = -3(x-4)^2 + 8y=−3(x−4) 2 +8

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step-by-step explanation:

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infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions