Somebody so i can pass, rewrite the following equation in the form y = a(x - h)2 + k. then, determine the x-coordinate of the minimum. y=2x^2 - 32x + 56 the rewritten equation is y = (x - )2 + . the x-coordinate of the minimum is

First, we are going to find the vertex of our quadratic. Remember that to find the vertex  of a quadratic equation of the form , we use the vertex formula , and then, we evaluate our equation at  to find .

We now from our quadratic that  and , so lets use our formula:




Now we can evaluate our quadratic at 8 to find :




So the vertex of our function is (8,-72)

Next, we are going to use the vertex to rewrite our quadratic equation:



The x-coordinate of the minimum will be the x-coordinate of the vertex; in other words: 8.

We can conclude that:
The rewritten equation is 
The x-coordinate of the minimum is 8