Find the average value fave of the function f on the given interval. f(x) = x2/(x3 + 14)2, [−2, 2] fave =

Let  x  indicate the dimensionless quantity  x  = k/k  f  . in the  interval  0 ≤  x  ≤ 1 the  function f(x) varies from 1 to 1/2; it is easily seen that its  average value  is just 3/4; in fact  fav= ∫ 1 0 x2f(x)dx /∫ 1 0 x2dx=3 ∫ 1 0 x2f(x)dx=34. (c.5) the indefinite integral ∫  x(1−x2)ln1+x1−xdx= 1  2 x−  1 6  x3− 14(1−x2)2ln1+x1−x  has been 

Yuh yeet honestly idk