An expression is shown below: f(x) = 4x2 + 8x − 5 part a: what are the x-intercepts of the graph of f(x)? show your work. (2 points) part b: is the vertex of the graph of f(x) going to be a maximum or minimum? what are the coordinates of the vertex? justify your answers and show your work. (3 points) part c: what are the steps you would use to graph f(x)? justify that you can use the answers obtained in part a and part b to draw the graph. (5 points) pls

F(x) = 4x2 + 8x − 5 should be written as  f(x) = 4x^2 + 8x − 5.  at any x-intercept, y would be zero.  thus, set  4x^2 + 8x − 5 = 0 and solve for x.  you could use the quadratic formula, or completing the square, or any of several other approaches.y = 4x^2 + 8x − 5  =  4(x^2 + 8x        +16 - 16            )  - 5, or                                    4(x^2 + 8x + 16) -5 -64, or                                y = 4(x+4)^2 - 69to find the x-intercepts, solve either y = 4(x+4)^2 - 69 = 0 or    4x2 + 8x − 5 = 0.  (the roots should be / must be the same)because the coeff. of x^2 is positive, the graph of the quadratic opens up, and thus the vertex represents the min of the function.