Aline has a slope of - 3/5. which ordered pairs could be points on a line that is perpendicular to this line? check all that apply. (–8, 8) and (2, 2) (–5, –1) and (0, 2) (–3, 6) and (6, –9) (–2, 1) and (3, –2) (0, 2) and (5, 5)

(–3, 6) and (6, –9) and  (0, 2) and (5, 5)

Step-by-step explanation:

Given : Slope = .

To find: Which ordered pairs could be points on a line that is perpendicular to this line.

Solution : We have given that  Slope = .

Slope = .

For (–8, 8) and (2, 2)

Slope = .

Slope = .

Slope = .

For (–5, –1) and (0, 2).

Slope = .

Slope = .

For, (–3, 6) and (6, –9)

Slope = .

Slope = .

Slope = .

For (–2, 1) and (3, –2)

Slope = .

Slope  = .

For (0, 2) and (5, 5)

Slope = .

Slope =  .

Therefore,  (–3, 6) and (6, –9) and  (0, 2) and (5, 5)

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

happy to

pls mark as brainliest