Awater sprinkler sprays water over a distance of 25 feet and rotates through an angle of 130 degrees. find the area of the lawn sprinkled

This is a question of finding the area of a portion of a circle with a radius equivalent to the distance in which the water is sprayed. Such is given as,

A = πR^2* (∅/360), where R = radius of the circle, ∅= Angle of rotation

Substituting;
A = π*25^2*(130/360) = 709.04 ft^2