Adart is thrown at the board shown. it hits the board at a random point. find the probability that it will land in the unshaded region. round to the nearest percent. 75% 48% 67% 33%

The probability that it will land in the unshaded region in the nearest percent is:

                                       67%

We know that a full circle covers a angle of 360° or 2π radians.

The angle that is covered in the unshaded region is: 240°

Hence, the probability is calculated as the ratio of the number of favorable outcome to the total number of outcomes.

The probability in percentage that the dart will land in the unshaded region is:

Ratio of the angle of unshaded region to the angle of the total circle.

        Hence, to the nearest percent the probability is:

                       67%

you need to show the graph

step-by-step explanation:

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3