The height y (in feet) of a ball thrown by a child is where x is the horizontal distance in feet from the point at which the ball is thrown a).how high is the ball when it leaves the child's handb).what is the maximum high of the ballc).how far from the child does the ball strike the ground

a) 3 ft

b) 67 ft

c) 64.741 ft.

Step-by-step explanation:

Let as consider the height y (in feet) of a ball thrown by a child is

where x is the horizontal distance in feet from the point at which the ball is thrown

.

(a)

We need to find the initial height of the ball.

Substitute x=0 in the given equation.

Therefore, the height of ball is 3 ft when it leaves the child's hand.

(b)

If a quadratic equation is defined as

then the vertex of the function is

In the given equation and b=4. So,

Substitute x=32 in the given equation.

The vertex of the parabola is (32,67). So, the maximum height of the ball is 67 ft.

(c)

The height of the ball is zero when it touch the ground.

Substitute y=0 in the given function.

Using quadratic formula, we get

The distance can not be negative. So the ball will touch the ground at the distance of 64.741 ft.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.