Light is incident on a double-slit. the fourth bright band has an angular distance of 7.0° from the central maximum. what is the distance between the slits (in mm)? (assume the frequency of the light is 5.4 ´ 1014 hz.)

The distance between the slits is about 1.8 × 10⁻² mm

Let's recall the Young's double-slit formula as follows:

where:

d = distance between the slits ( m )

θ = angular distance

n = order number

λ = wavelength ( m )

Let us now tackle the problem!

Given:

angular distance = θ = 7.0°

frequency of the light = f = 5.4 × 10¹⁴ Hz

order number = n = 4

speed of light = v = 3 × 10⁸ m/s

Asked:

distance between the slits = d = ?

Solution:

The distance between the slits is about 1.8 × 10⁻² mm

Grade: High School

Subject: Physics

Chapter: Light

most of them using statistics and defining how things are being measured

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.