Aperson standing at the top of mountain aconcagua would be approximately 4.3 mi high. the radius of earth is 3959 mi. what is the distance to the horizon from this point? enter your answer as a decimal in the box. round only your final answer to the nearest tenth. mi

The height of the person and mountain, the radius of the earth, and the distance to the horizon formulate a relationship of Pythagorean theorem.  

Thus , hypotenuse = sum of the radius of the earth and the height of the person and mountain.

C = 3959 mi + 4.3 mi

   = 3963.3 mi

C2 = A2 + B2

B=√C2−A2

B =√(3963.3 mi)2−(3959)2

B =184.6 mi

The distance to the horizon is 184.6 mi

d) the number of neutrons plus the number of protons

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂