To increase the brightness of a desk lamp, a student replaces a 50-watt incandescent lightbulb with a 100-watt incandescent lightbulb. compared to the 50-watt lightbulb, the 100-watt lightbulb has (1) less resistance and draws more current (2) less resistance and draws less current (3) more resistance and draws more current (4) more resistance and draws less current

From the formula for Electric Power, P = IV,    P = V²/R

So the 100W compared to the 50W.

From P = IV. From the equation there is a direct relationship between P and I.  More  Power P means more Current, I.

From P = V²/R. From the equation, there is an inverse relationship
between P and R. Therefore  more P means less R. 

So from these assertions, the answer is: 

(1) less resistance and draws more current

B) raising the temperature and reducing the volume of the gas.|-/ 

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward