Physics, 15.07.2019 16:30 yadirachavez2002

When a resistor with resistance r is connected to a 1.50-v flashlight battery, the resistor consumes 0.0625 w of electrical power. (throughout, assume that each battery has negligible internal resistance.) what power does the resistor consume if it is connected to a 12.6-v car battery? assume that r remains constant when the power consumption changes?

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Answer from: Cedars6976

The power consumed by the resistor if it is connected to a 12.6-V car battery is 4.41 Watts.

Given the following data:

Voltage = 1.5 VoltsPower = 0.0625 WattsEmf = 12.6 Volts

To find the power consumed by the resistor if it is connected to a 12.6-V car battery:

First of all, we would determine the value of this resistor by using the following formula;

$Power = \frac{Voltage^2}{Resistance}$

Substituting the parameters into the formula, we have;

$0.0625 = \frac{1.5^2}{Resistance}$

Cross-multiplying, we have:

$0.0625(Resistance) = 1.5^2\\\\Resistance = \frac{1.5^2}{0.0625}\\\\Resistance = \frac{2.25}{0.0625}$

Resistance = 36 Ohms

Now, we can find the power consumed by the resistor if it is connected to a 12.6-V car battery (resistance remained constant):

$Power = \frac{Voltage^2}{Resistance}$

Substituting the parameters into the formula, we have;

$Power = \frac{12.6^2}{36}\\\\Power = \frac{158.76}{36}$

Power = 4.41 Watts.

Therefore, the power consumed by the resistor if it is connected to a 12.6-V car battery is 4.41 Watts.

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Answer from: Tenika1

The key to unlock this complicated mystery is to know the value of the resistor. We can calculate it from the description of Scene 1:

Power dissipated by a resistance = (voltage)² / (resistance)

Resistance = (voltage)² / (power)

In scene 1:

Resistance = (1.5 v)² / (0.0625 w)

Resistance = 36 Ohms

That helps a bunch ! It's all we need to solve the second part.

Power = (voltage)² / (resistance)

Power = (12.6 v)² / (36 Ω)

Power = 4.41 watts

Another (easier) way:

Power = (voltage)² / (resistance)

SO ... if the resistance doesn't change, then the power
is proportional to the square of the voltage.

(power₂ / power₁) = (voltage₂ / voltage₁)²

power₂ = (power₁) · (voltage₂ / voltage₁)²

power₂ = (0.0625 w) · (12.6v / 1.5v)²

power₂ = (0.0625 w) · (8.4)²

power₂ = (0.0625 w) · (70.56)

power₂ = 4.41 w

Answer from: Quest

spare some change and give it to the poor

explanation:

plz : ((

Answer from: Quest

bacteria that live on the ocean floor are sustained by phytoplankton. phytoplankton, microscopic marine photosynthetic organisms, have a vastly significant role to play not only in the marine food web of which they’re part of, but also on a more global scale. despite their infinitely small size in comparison to other marine organisms, these tiny creatures occupy an immensely important ecological niche: they are the foundation of the marine food web, and as primary producers, play key roles in supporting all other organisms in the marine environment, as well as in the regulation of the earth’s climate through the sequestration of carbon, oxygen production, and other related processes. phytoplankton account for roughly half of all global primary productivity; therefore, their significance extends far beyond the marine environment alone. there is an intriguing sense of irony in the realization that these tiny living beings that often live out their existence unnoticed and undetected by the rest of the world, have such a far-reaching impact on the lives of virtually all other living organisms on the planet, particularly on those in the marine environment. the world that we have become accustomed to has been and is continuously shaped by the workings of these miniscule yet vital “plants of the sea”.

hope this !

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