Aforce of 1.5 × 102 n is exerted on a charge of 1.4 × 10–7 c that is traveling at an angle of 75° to a magnetic field. if the charge is moving at 1.3 × 106 m/s, what is the magnetic field strength? 8.2 × 102 t 8.5 × 102 t 3.2 × 103 t 6.4 × 1010 t

Option (B) is correct.The magnetic field strength=8.5 x 10² T

Explanation:

the magnetic force Fm is given by

Fm= q V B sinθ

q= charge=1.4 x 10⁻⁷ C

v= velocity= 1.3 x 10⁶ m/s

B= magnetic field strength

Fm= magnetic force= 1.5 x 10² N

θ=75°

so 1.5 x 10²=(1.4 x 10⁻⁷) (1.3 x 10⁶ ) (B) sin75

B=8.5 x 10² T

B

Explanation:

the answer is a. at the equator

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