A0.54 kg particle has a speed of 5.0 m/s at point a and kinetic energy of 7.5 j at point b. what is (a) its kinetic energy at a? (b) its speed at point b? (c) the total work done on the particle as it moves from a to b?

Answers

(a)  6.75 Joules.

(b)  5.27 m/s

(c) 0.75 Joules

Explanation

Kinetic energy is the energy possessed by a body in motion.

(a) its kinetic energy at A?

K.E = 1/2 mv²

       = 1/2 ×  0.54 × 5²

       = 6.75 Joules.

(b) its speed at point B?

K.E = 1/2 mv²

7.5 = 1/2 × 0.54 × V²

V² = 7.5 ÷ 0.27

     = 27.77778

V = √27.77778

   = 5.27 m/s

(c) the total work done on the particle as it moves from A to B?

Work done = 7.5 - 6.75

                 = 0.75 Joules

your answer is, orbit around the nucleus

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2