As the distance from equilibrium decreases, in what way is the magnitude of the force on an object that is undergoing simple harmonic motion affected? a. it increases. b. it decreases. c. it remains the same.

The correct answer is B. The force decreases.

Simple harmonic motion is a to and fro motion about the equilibrium position, with the restoring force proportional to the displacement and it is always directed towards the mean position.

Mathematically, the force F is given by,

Here, x is the displacement from the equilibrium position and k is the force constant. The negative sign indicates that the direction of the force is always directed towards the equilibrium position, opposite to the direction of the displacement from the equilibrium position.

Thus, as the displacement from the equilibrium position decreases, the force acting on the body also decreases.

the pull of gravity on the rocket decreases

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.