The specific gravity of gasoline is approximately 0.70. (a) estimate the mass (kg) of 50.0 liters of gasoline. (b) the mass flow rate of gasoline exiting a refinery tank is 1150 kg/min. estimate the volumetric flow rate in liters/s. (c) estimate the average mass flow rate lbm/min? ? delivered by a gasoline pump. (d) gasoline and kerosene specific gravity ? ? 0: 82? ? are blended to obtain a mixture with a specific gravity of 0.78. calculate the volumetric ratio (volume of gasoline/volume of kerosene) of the two compounds in the mixture,

a)

b)

c)

d) V_k : V_g = 2 : 1

Explanation:

Given:

specific gravity of gasoline,

∴density of gasoline,

(a)

volume of gasoline,

We know ,

& mass is related as:

(b)

We have,

mass flow rate of gasoline,

So, volume flow rate:(assuming the flow to be in-compressible)

(c)

∵1 kg = 2.20462 lbm

∴1150 kg = 1150×2.20462 lbm

So,

(d)

specific gravity of  kerosene,

∴density of kerosene,

new density after mixing kerosene with gasoline,

We know  that:

and by the law of conservation of mass & volume:

where = new volume

So,

where =volume of kerosene.

V_k : V_g = 2 : 1

if they have a finite resultant