An old truck compresses a spring scale at the junkyard by 25 cm. the spring constant for the industrial scale at the junkyard is 39,200 n/m what is the force applied to the scale by the car?

Force applied to the scale by the car is 9800 N.

Explanation:

It is given that,

A spring scale is compresses by an old truck such that, x = 25 cm = 0.25 m

The spring constant for the industrial scale at the junkyard is, k = 39200 N/m

We need to find the force applied to the scale by the car. It can be calculated using the following relation as per Hooke's law :

F = -k x

negative sign shows the direction of force

F = 9800 N

So, the force applied to the scale by the car is 9800 n. hence, this is the required solution.

false

explanation:

boats, things on boats luggage are way more heavy then water.

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.