The driver of a car wishes to pass a truck that is traveling at a constant speed of 20.5 m/s . initially, the car is also traveling at a speed 20.5 m/s and its front bumper is a distance 23.9 m behind the truck's rear bumper. the car begins accelerating at a constant acceleration 0.640 m/s2 , then pulls back into the truck's lane when the rear of the car is a distance 26.3 m ahead of the front of the truck. the car is of length 4.90 m and the truck is of length 20.2 m

total distance moved by the car

now given that the acceleration of the car is

a = 0.640 m/s^2

initial speed of both is given same so relative speed is zero

now we can use kinematics

so it will take 15.33 s to overtake and reach the given distance

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.