Anna is driving from champaign to indianapolis on i-74. she passes the prospect ave. exit at noon and maintains a constant speed of 75 mph for the entire trip. chuck is driving in the opposite direction. he passes the brownsburg, in exit at 12: 30pm and maintains a constant speed of 65 mph all the way to champaign. assume that the brownsburg and prospect exits are 105 miles apart, and that the road is straight. how far from the prospect ave. exit do anna and chuck pass each other?

The distance from the prospect ave. where Anna and Chucks pass each other is 73.5 miles

The given parameters;

The distance traveled by Anna before Chucks start is calculated as;

The new distance between Anna and Chucks when Chucks started moving;

The time when the two meet is calculated by applying relative velocity formula;

The distance form the prospect ave. exit when Anna and Chucks passes each other;

This distance will be equal to the initial distance traveled by Anna and distance to where she passes Chucks

Thus, the distance from the prospect ave. where Anna and Chucks pass each other is 73.5 miles

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Let they both meet after time "t" after Chuck leaves the city

So Monica will move for time "t + 0.5" h as she leave before half an hour

so in this time the sum of distance covered by both of them must be equal to the total distance between them initially

so we have

so the total time after which they both will meet is 0.48 hours or 28.9 minutes

Now the distance of the point of intersection from Prospects is given as

so the distance from Prospects is 73.5 miles

a and b sometimes have a positive value

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it