What is the mass of a magnesium block that measures 2.5cm x 3.5cm x 1.5cm?

22.8 g

Explanation:

1) density = mass / volume ⇒ mass = density × volume

2) density of magnesium = 1.74 g/cm³ (from internet)

3) volume of a block = length × width × depth

  volume of the magnesium block = 2.5cm × 3.5 cm × 1.5 cm = 13.125 cm³

4) mass of the magnesium block = 1.74 g/cm³ × 13.125 cm³ = 22.8375 g.

Rounding to 3 significant figures, mass = 22.8 g ← answer

The mass of the magnesium block is found to be 22.8 g.

Density of a substance is defined as mass per unit volume.

Calculate the volume V of the magnesium block using the dimensions given in the problem.

Magnesium has a density ρ of 1.74g/cm³. This can be taken from the standard tables.

Since density is mass per unit volume,

The mass of the block is therefore given by,

Substitute  1.74g/cm³for  ρ and 13.125 cm³for V.

The mass of the magnesium block is found to be 22.8 g.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

god i hope this !