Small frogs that are good jumpers are capable of remarkable accelerations. one species reaches a takeoff speed of3.7 m/s in60 ms . part a what is the frog's acceleration during the jump?

We know that acceleration is change in velocity by time taken for that change.

In this case velocity change is 3.7 m/s

Time taken for this change = 60 ms =

So acceleration of frog  =

                                       = 61.66 m/

So acceleration of frog is 61.66 m/

o it is evident that frog is capable of remarkable accelerations.

The frog's acceleration during the jump is 62 m/s²

Acceleration is rate of change of velocity.

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

Given:

initial speed = u = 0 m/s

final speed = v = 3.7 m/s

time taken = t = 60 ms = 0.06 s

Unknown:

acceleration = a = ?

Solution:

To find the acceleration of th frog, it can be done in the following way:

The frog's acceleration during the jump is 62 m/s²

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate, Frog , Jump

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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