Aspacecraft is traveling with a velocity of +3250 m/s. suddenly the retrorockets are fired, and the spacecraft begins to slow down with an acceleration whose magnitude is 10.0 m/s2. how far does the spacecraft travel until it comes to a momentary halt?

Answer;

= 528 km

Explanation;

Assuming the question is how far would you be from the asteroid when your relative velocity is zero.  

The time taken to stop is 3250/10 = 325 secs  

and your average velocity is 3250/2  

So, the distance traveled is 3250 * 325 /2 = 528 km  

Alternatively;

- if you started with v^2 = 2as  

to get s = v^2/(2a) you get exactly the same calculation and of course the same result.

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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