The bar ab has a velocity at point a of va = [20,9] m/s and an angular velocity w = 23 rad/s. if the distance between a and b is .71 m what is the speed of point b

speed of point A is given as

here r = distance from the axis

so here we have

now the distance of point A and B is 0.71 m

while the distance of axis from point A is 0.91 m

so distance of axis from point B will be given as

now for the speed of point b is given as

so end point B will move with speed 37.26 m/s

answer: point c: b. 1/2 potential, 1/2 kinetic, point a: 3/4 of its potential energy, point d or b: 3/4 potential, 1/4 kinetic

explanation: i cant explain. it's difficult to explain.

the answer is 3.1 his answer is wrong mines is right