Arace car enters the circular portion of a track that has a radius of 63 m. when the car enters the curve at point p, it is travelling with a speed of 120 km/h that is increasing at 5 m/s2.

When car enters a circular path its speed is increasing at rate 5 m/s^2

so this is the tangential acceleration of car

now at the same time since car is moving along the curved path so it must have centripetal acceleration at the same time

It is given by equation

so now the net acceleration of the car is given as

ice to water 1 water to vapour 2 latent heat

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s