An object initially moving 10 m/s accelerates for 6 seconds. if it moves 134 m, find the acceleration. a. 49.3 m/s^2 b.1.02 m/s^2 c.4.11 m/s^2 d.6.17 m/s^2

Acceleration of the object is 4.11 .

Given:

Initial velocity = 10

Time = 6 second

Distance = 134 meter

To find:

Acceleration of the object = ?

Formula used:

s = u t +

Where s = distance covered by object

u = initial velocity of the object

t =  time taken by object

a = acceleration of the object

Solution:

According to second equation of motion the distance of the object is given by,

s = u t +

Where s = distance covered by object

u = initial velocity of the object

t =  time taken by object

a = acceleration of the object

134 = 10 (6) +

134 - 60 = 18 a

74 = 18 a

a =

a = 4.11

Hence, acceleration of the object is 4.11 .

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

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explanation: