An object moving on the x axis with a constant acceleration increases its x coordinate by 82.9 m in a time of 2.51 s and has a velocity of 20 m/s at the end of this time. determine the acceleration of the object during this motion.

We are given: Final velocity ()=20 m/s .

Time t= 2.51 s and

distance s = 82.9 m.

We know, equation of motion

Let us plug values of final velocity, and time in above equation.

Subtracting 2.51a from both sides, we get

 -----------equation(1)

Using another equation of motion

Plugging values of vi =20-2.51a, t=2.51 and distnace s=82.9 in this equation.

We get,

Now, we need to solve it for a.

20-20+2.51a=165.8a.

-163.29a=0

a=0.

So, the acceleration would be 0 m/s^2.

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