In a slap shot, a hockey player accelerates the puck from a velocity of 8.00 m/s to 40.0 m/s in the same direction. if this shot takes 3.33×10 −2 s, calculate the distance over which the puck accelerates.

We use the equations of motion,

                                              (A)

                               (B)

Here, v is final velocity of the body, u is initial velocity of the body, a is the acceleration of the body, t is the time taken in the motion and s is distance traveled by the body.

Given , and .

So, from equation (A)

Now from the  equation (B),

Thus, the distance over which the puck accelerates is 0.8 m.

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

explanation:

as the height from which the ruler was dropped increased, the speed of the ruler at ryan's hand increased.