It is possible to shoot an arrow at a speed as high as 102 m/s. (a) if friction is neglected, how high would an arrow launched at this speed rise if shot straight up?

An arrow at a speed as high as 102 m/s straight up will travel 530.82 m height

Explanation:

   We know the equation of motion , where s is the displacement, u is the initial velocity, a is the acceleration and v is the final velocity.

  In this case body is projected straight up, so final velocity = 0 m/s, initail velocity = 102 m/s, acceleration = -9.8 and we need to find displacement, that is the height traveled by arrow.

   Substituting

   So height traveled by arrow = 530.82 m

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

it about 600 mph from what i calculated