If a seagull drops a shell from rest at a height of 12 m how fast is the shell moving when it hits the rocks

As seagull drops a shell from rest at a height of 12 m, so we use kinematic equation of motion,

Here, h is the height, u is initial velocity , v is final velocity and g is acceleration due to gravity.

Given,  h = 12 m.

We take, and because seagull drops a  shell from rest.

Therefore, the speed of shell when it hits the rocks,

answer: the correct answer is   air pressure at the top of mount everest is higher than at the bottom of the grand canyon.

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explanation: