An object is fired from the ground at 200 meters per second at an angle of 30* with the horizontala. calculate the horizontal and vertical components of the initial velocityb. after 6.0 seconds how far has the object traveled on the horizontal directionc. how high is the object at this point

Horizontal component = V cos(30°) = V (√3/2) = 73.2 m/s

Vertical component = V sin(30°) = V (0.5) = 100 m/s

In 6 seconds, the object travels horizontally (173.2 m/s x 6 sec) = 1,039 m

After 6 seconds, the object's height above the ground is

H = V₀t + 1/2 a t²

H = (100 m/s)(6 s) + (1/2) (-9.8 m/s²) (6 s)²

H = (600 m) - (4.9 m/s²) (36 s²)

H = (600 m) - (176.4 m)

Height = 423.6 m

32: from largest to smallest, this hierarchy includes eons, eras, periods, epochs, and ages.

33: answer is c

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this could be newton#'s law of cooling. the cooling curve is exponential