Aconstant force of 12n is applied for 3.0s to a body initially at rest. the final velocity of the body is 6.0ms–1. what is the mass of the body?

From the question,






Using Impulse, the product of the constant force, F and time t equals the product of the mass of the body and change in velocity.




This implies that





You can also use the equation of linear motion,






But

It is the areas with lines. this may sound a little confusing, but i hope it !

At maximum height, kinetic energy is converted in potential energy  formula: at max height, ke = ½ * 0.27kg * (16m/s) ² = 34.56 j  so the remaining pe = (41.70 – 34.56)= 7.14 j = 0.27 kg * 9.8m/s² * h  = (9.8/7.14 * 0.27)so max height h = 5.08 or 5 m