Aworker pushes a large rock to the north while another worker by pushing it to the east. if they both exert equal force, in what direction does the rock move? question 2 options: northeast east north southwest

let the magnitude of force applied by each worker be "F"

consider east-west direction along X-axis and north-south direction along Y-axis

In unit vector form, force vector by worker pushing in east direction is given as

= F + 0  

In unit vector form, force vector by worker pushing in north direction is given as

= 0 + F  

resultant force is given as the vector sum of two vector forces as

= +

= (F + 0   ) + (0 + F   )

= F +  F  

direction of the force is hence given as

θ = tan⁻¹(F/F)

θ =  tan⁻¹(1)

θ = 45 degree north of east

hence the direction is north-east

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.