Astuntwoman is going to attempt a jump across a canyon that is 77 m wide. the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave. the takeoff ramp is built with a 15º angle from horizontal. if the stuntwoman leaves the ramp with a velocity of 28 m/s, will she make the jump? why?

initial speed of the stuntman is given as

angle of inclination is given as

now the components of the velocity is given as

here it is given that the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave.

So the displacement in vertical direction is given as

by solving above equation we have

Now in the above interval of time the horizontal distance moved by it is given by

since the canyon width is 77 m which is less than the horizontal distance covered by the stuntman so here we can say that stuntman will cross the canyon.

answer: i don't know the answer good luck

explanation: