Suppose that a small french bulldog grows isometrically. if its surface area increases by a factor of 3, by what factor does its volume increase by?

Here's the handy factoid I always carry around in my toolbox:

When the three dimensions of a solid object all change by a factor of ' K ' . . . .

--  the surface area of the object changes by a factor of  K²

-- the volume of the object changes by a factor of  K³ .

So I guess if the surface area increases by 3, that means each linear dimension increased by √3, and the volume has to increase by  (√3)³ .  

That's 5.196 times the dog's original volume.

(And so does his weight.  The poor thing is staggering around wondering what was in that last bowl of kibble that he inhaled.)

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever