What is the maximum speed with which a 1200-kg car can round a turn of radius 88.0 m on a flat road if the coefficient of static friction between tires and road is 0.40?

18.6 m/s

Explanation:

The frictional force acting on the car is given by:

But the frictional force also corresponds to the centripetal force that keeps the car in circular motion in the turn:

Where v is the maximum speed the car can achieve remaining in the turn. Substituting r=88.0 m and re-arranging the formula, we can find the value of v:

answera compound;