Alacrosse ball leaves the sick horizontally at 12.0m/s. the catcher is 14.0 away. how much does the ball fall vertically travelling halfway to the catcher?

1.65 m

Explanation:

The motion of the ball is a projectile motion, so it is a parabolic motion with two independent motions:

- on the x-axis, a uniform motion with constant speed

- on the y-axis, a uniformly accelerated motion with constant acceleration downward.

First of all, we need to find the time t at which the ball has travelled halfway to the chatcher, i.e. at a distance of . This can be found by using the relationship between distance, time and velocity along the horizontal direction:

So now we can move to the vertical motion, and we can calculate the distance covered vertically by the ball while falling for t=0.58 s, by using:

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